Charles, Dilip and Ezekiel always share their sweets in the ratio 1:3:2.

a)     On Monday they have 48 sweets altogether.
        How many do they get each?

As before, we set out the question in a ratio form,
write the portions and total,
then multiply the ratio. [by 8, obviously!]

Charles	:	Dilip	:	Ezekiel
1	:	3	:	2	6
8	:	24	:	16	48

b)     On Tuesday, when they share out their sweets, Dilip gets 33.
        How many sweets did they start with?

Set out the ratio form as normal,
but this time write the portions and Dilip's sweets.

Charles	:	Dilip	:	Ezekiel
1	:	3	:	2	6
	:	33	:

This shows us the multiplying factor [11, obviously!]
We can then fill in the missing values:

Charles	:	Dilip	:	Ezekiel
1	:	3	:	2	6
11	:	33	:	22	66

c)     On Wednesday they start with fifty-four sweets
        and divide them up as normal but then Dilip gives
        three sweets to Charles and six sweets to Ezekiel.

        Describe the number of sweets they have now
        as a ratio in its simplest form.

As in the first part, we set out the ratio, portions and total,
then multiply. [by 9, obviously!]

Charles	:	Dilip	:	Ezekiel
1	:	3	:	2	6
9	:	27	:	18	54

Now we need to reallocate the sweets as per the question:

Charles	:	Dilip	:	Ezekiel
9+3	:	27-3-6	:	18+6	54
12	:	18	:	24	54

Finally we need to re-write this ratio in its simplest form.
We have to divide each value by the LCM of the three numbers.
This is of course six!

Charles	:	Dilip	:	Ezekiel
12	:	18	:	24
2	:	3	:	4

Finished!